General Discussion

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  SOLVED A little arcTo() and geometry help?
  bezierpath recreations trigonometry • • MauriceMeilleur  

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  The finished product, a tribute to Bridget Riley's Rustle 6 (2015). import math canvasX = 600 canvasY = 600 nFrames = 120 side = canvasX/14 height = (side * sqrt(3))/2 center = (side/sqrt(3))/2 nX = 14 nY = 15 offsetX = side offsetY = height from datetime import * time = datetime.now() def interpolate(pt1, pt2, ratio): assert ratio <= 1 return (pt1[0] + (ratio * (pt2[0] - pt1[0])), pt1[1] + (ratio * (pt2[1] - pt1[1]))) def triangle(s, h, c, inout): assert inout >= 0 and inout <= 1 start = (-s/2, h/2) pivot = (0, h/2 - (c * 3)) target = (s/2, h/2) control = interpolate((s/2, -c/2), (0, h/2 - c), inout) radius = s # optimal distance to control points is (4/3)*tan(pi/(2n); thank you https://stackoverflow.com/users/16673/suma for answering this question https://stackoverflow.com/questions/1734745/how-to-create-circle-with-b%C3%A9zier-curves control_ratio = ((4/3 * tan(pi/12)) * radius) / (2 * c) controlP = interpolate(pivot, control, control_ratio) controlT = interpolate(target, control, control_ratio) triangle = BezierPath() triangle.moveTo(start) triangle.lineTo(pivot) triangle.curveTo(controlP, controlT, target) triangle.closePath() drawPath(triangle) def frame(x, y, m): f = BezierPath() g = BezierPath() f.rect(0, 0, x, y) g.rect(m, m, x - (2 * m), y - (2 * m)) f = f.difference(g) f.closePath() drawPath(f) # original Riley plan for Rustle 6 plan = [ [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 1, 0, 0, 0, -1, 0, 0, 0, 1, 0, 0], [-1, 0, -1, 0, 0, 0, 0, 0, 1, 0, -1, 0, 0], [1, 0, 1, -1, 0, 0, -1, 0, 0, 0, 1, 0, 1, 0], [0, -1, 0, -1, 0, 0, 0, 1, 0, -1, 0, -1, 0], [0, 1, -1, 1, 0, 1, 0, 0, 0, 0, -1, 1, 0, 0], [-1, 0, -1, 0, 0, 0, 0, 0, 0, 0, -1, 0, -1], [1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0], [0, -1, 0, 0, 0, 0, 0, 0, 0, -1, 0, -1, 0], [0, -1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, -1, 0], [-1, 0, -1, 0, 0, 0, 0, 0, 0, 0, -1, -1, -1], [-1, 0, -1, 0, 1, 0, 1, 0, 0, 0, 1, -1, -1, 0], [0, -1, 0, 0, 0, 0, 0, 0, 0, -1, 0, -1, -1, 0], [0, 0, 0, -1, 0, 0, 0, 0, 0, 0, 0, -1, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], ] for n in range(nFrames): newPage(canvasX, canvasY) frameDuration(1/30) ex = sin(radians(n * (360/nFrames))) fill(1) rect(0, 0, canvasX, canvasY) with savedState(): translate(canvasX/2, canvasY/2) fill(0) translate(-(nX - 1) * offsetX/2, (nY - 1) * offsetY/2) for i in range(nY): with savedState(): translate(0, i * -offsetY) if i % 2 == 0: for j in range(nX - 1): with savedState(): translate(offsetX/2 + (j * offsetX), 0) triangle(side, height, center, .5 - (ex * (plan[i][j] * .5))) else: for j in range(nX): with savedState(): translate(j * offsetX, 0) triangle(side, height, center, .5 - (ex * (plan[i][j] * .5))) fill(1) frame(canvasX, canvasY, side/2) saveImage('~/Desktop/riley_tribute_test_01_%s.gif' %time) The reference image:
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  SOLVED draw arc
  bezierpath trigonometry arc • • Manufraktur  

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  Dear @gferreira, I tried to use your suggestion it in my exercise and it worked fine. Thank you so much for your help! Amazing. Thank you and kind regards, Petra
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  SOLVED fontVariations in BezierPath or formattedString
  bezierpath variable fonts featurevariations formattedstring • • erik  

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  hello @erik, yes, see this example. groeten!
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  SOLVED Using global variables input
  drawbot as module user interaction variables drawbot package vanilla • • snaders  

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  Hello @gferreira, Thanks for the quick reply. I mistakenly thought vanilla just ment that it didn't have any 'addons'. Like vanilla JS... This makes a lot more sense, will look into that! Thanks a lot!
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  SOLVED Find out whether a point is placed within an area
  • jansindl3r  

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  @jansindl3r yes, have a look at BezierPath.pointInside(xy)
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  SOLVED How can I split a path into multiple segments?
  bezierpath • • jansindl3r  

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  there’s an example of FlattePen + BezierPath here
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  SOLVED Newby request
  bezierpath geometry boolean operations • • KevinKarney  

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  hello @KevinKarney, welcome to DrawBot! 1. I need the option to build compound objects (with unions, differences, intersections). Is it possible to make (e.g) a torus by differencing 2 circles. Or do I have to create two bezier paths and then do the difference. both methods are possible: you can do it with a single BezierPath by drawing two circles in opposing directions: x, y = 500, 500 r1 = 400 r2 = 300 B = BezierPath() B.oval(x-r1, y-r1, r1*2, r1*2) B.reverse() B.oval(x-r2, y-r2, r2*2, r2*2) fill(0, 1, 0) stroke(1, 0, 0) strokeWidth(10) drawPath(B) or you can draw two separate circles, and get the difference between them: B1 = BezierPath() B1.oval(x-r1, y-r1, r1*2, r1*2) B2 = BezierPath() B2.oval(x-r2, y-r2, r2*2, r2*2) B3 = B1.difference(B2) drawPath(B3) 2. with primitives such as oval or rect, can I incorporate the fill, stroke, strokewidth, etc into the call. In Nodebox 1, I can say (e.g) a = rect(0,0,20,20,stroke=Red,strokewidth=3,fill=Grey, draw=False) This creates an object call a, but does not draw it.... grouping colors and geometry can be done with functions: def a(): stroke(1, 0, 0) strokeWidth(3) fill(0.5) rect(0, 0, 20, 20) a() hope this helps… have fun with the movies, and let us know if you have any other questions.
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  SOLVED some problems importing noise module
  modules noise • • rachelkriebel  

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  hello @burnier & everyone else with the same problem, the latest version of Python is 3.7 DrawBot currently embeds Python 3.6 if you recently installed “Python 3” from python.org, you probably have 3.7. to make modules available in DrawBot, they need to be installed for Python 3.6 (not 3.7). so, the first step is to make sure that you have Python 3.6 installed in your system. you can check that by typing python3.6 in Terminal. if you get -bash: python3.6: command not found, then you need to install Python 3.6 first. you can get it from python.org/downloads. pip is included in Python, so once you have Python 3.6 you should have pip3.6 too. please give it a try, and let us know how it goes… good luck!
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  SOLVED How to get width of text, including metrics?
  text • • jansindl3r  

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  @gferreira I also believe that you meant textSize('string')
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  SOLVED Place stroke on a shape's contour, with no offset
  stroke clipping outline • • jansindl3r  

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  hello @jansindl3r, you can use the contours of the letters as a clipping mask, so the outside half of the stroke is not visible: size(2000, 1000) stroke(1, 0, 0) strokeWidth(30) B = BezierPath() B.text('a', (110, 130), fontSize=1400) # clip external stroke with savedState(): clipPath(B) drawPath(B) # normal stroke translate(1000, 0) drawPath(B) cheers!
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  SOLVED How to mirror/flip a object?
  transformations • • habakuk  

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  Hallo @jo thanks alot - at the moment i use the lissajus only to create different nice looking loops. I changed the values as you suggested and of course it is working now and delivers a new nice looking loop. I`d love to make some more loops with more "natural, subtle and slow" movements. I saw your great visualisations of the different variable font movements and hoped to create a custom path to do so - but i failed... if you like to play around with my very first 5 letter variable font (HABKU) you are very welcome. http://habaland.ch/images/habaroll8GX.ttf i added the the plus and minus to avoid the font doing the whole move to the min and max, because the backgraound would be visible then. (but most likely i created only a mess ) and by the way, i hate the black circle i had to ad "behind the scene" - id love o have a cleaner solution. ...at the moment i am trying to figure out where to append the savedState() without messing everything up... greetings from Bern
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  UNSOLVED Efficient way to convert all text to outlines in a multi-page doc?
  bezierpath text • • ThunderNixon  

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  mmm, generate an instance with fontTools, use that font with a path and generate the pdf? wondering if the Bad font object... error is also reported with old-style-static-fonts?
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  SOLVED Is there a way to build "bleed" into a file, for printing?
  layout • • ThunderNixon  

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  Until there's a new feature for this, I think you could replace your newPage() calls to a custom newPageWithBleed() that goes something like this, and wouldn't need to change any of your other drawing code — def newPageWithBleed(w, h, bleed): newPage(w + bleed * 2, h + bleed * 2) translate(bleed, bleed) W, H = 400, 400 bleed = 25 newPage(W, H) rect(0, 0, 20, 20) newPageWithBleed(W, H, bleed) rect(0, 0, 20, 20)
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  UNSOLVED Using arcTo() for variable-radius corner-rounding
  trigonometry • • MauriceMeilleur  

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  No one has replied

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  SOLVED How do I size an image with the ImageObject (or without)?
  image transformations • • ThunderNixon  

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  Ahh this is a very clear-headed approach. Thanks for showing me how it's done! This is very helpful.
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  UNSOLVED Vector/BezierPath distortion methods?
  bezierpath recreations transformations • • MauriceMeilleur  

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  I suspect there's a way to do it by somehow drawing the straight lines in the glyphs as curves and pulling the off-curve points various distances away from being collinear with the on-curve points, in one direction or another, as I change the position of those on-curve points. But, I still struggle to figure out how to tell which are which, in a list of a curve's points, or to write a set of on-curve and off-curve points to a curve to create a shape on purpose—I know what quadratic and cubic curves are, but the order/syntax of the points in the path escapes me. So it may be a long while before I figure anything out …
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  UNSOLVED Random Lines with no intersection
  randomness • • mrrouge  

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  @mrrouge ok if i got you right you want the function to return a value — in your case the height of the legs. this value could then be used in a while loop. while loops are quite helpful but might run forever if done incorrect. I adapted the code a bit so the legs function returns the length of the legs which is then added to the y value in the while loop. There is a check inside the while loop so it will run for a maximum of 3000 times. # ------------- # settings pw = ph = 500 amount_x = 10 cell_w = pw / amount_x max_h = 50 gap = max_h * .2 # ------------- # fucntion(s) def legs(pos, max_w, max_h): x, y = pos length = random() * max_h step_s = random() * max_w polygon((x - step_s, y) , (x, y + length), (x + step_s, y), close = False) return length # ------------- # drawings newPage(pw, ph) fill(None) stroke(0) strokeWidth(2) for x in range(amount_x): count = 0 y = -random() * max_h while y < ph: y += legs((x * cell_w + cell_w/2, y), cell_w/2, max_h) y += gap count += 1 if count > 3000: break and the while loop without the check: for x in range(amount_x): y = -random() * max_h while y < ph: y += legs((x * cell_w + cell_w/2, y), cell_w/2, max_h) y += gap
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  SOLVED Overlapping paths
  bezierpath remove overlap • • MauriceMeilleur  

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  I can't say for sure, but just thinking about the editing I'd been doing when I ran into the problem, open paths would be the more likely explanation. Anyway, it's working now—time to move on to new problems.
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  SOLVED determine centerpoint in irregular rectangle / create "composition"
  geometry • • mrrouge  

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  thanks @}->--
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  SOLVED Hi can somebody help me randomize shapes within a loop ?
  randomness • • mrrouge  

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  Cool thanks for your help ! Iam really struggling to find the right information in the reference