Hi,
Is it possible to convert a Drawbot drawing to a PIL format without saving it as an image and then opening/converting it with PIL?
Currently, I'm trying to process all glyphs from a font file with PIL, and I'm using Drawbot to generate images to process with PIL.
I hadn't thought about this solution!
Thanks, @frederik!
newPage("A4Landscape")
box_w, box_h = width()-100, height()-100
box_x, box_y = 50, 50
txt = FormattedString()
txt.fontSize(90)
txt.align("center")
txt.append("LOOOOOOOOOOOOOOONG STRING\n"*30)
txt_w = textSize(txt)[0]
txt_h = textSize(txt)[1]
width_ratio = box_w/txt_w
height_ratio = box_h/txt_h
sf = min(width_ratio , height_ratio, 1)
scale(sf)
textBox(txt, (box_x/sf, box_y/sf, box_w/sf, box_h/sf))
Hi,
I'm looking for a solution to find the maximum value of FontSize that can be set to allow a FormattedString() to occupy all the available space in a TextBox.
For TextBox using a simple string, I have already coded this snippet that returns the maximum fontSize value:
def get_max_fontSize_textBox(font, text, box, align=None, fS=200):
font(FONT)
fontSize(fS)
hyphenation(False)
overflow = textOverflow(text, box, align)
while overflow:
font(FONT)
fS -= 1
fontSize(fS)
overflow = textOverflow(text, box, align)
return fS
I would like to achieve exactly the same thing, but using FormattedString() instead of a str.
The problem is how to build again the FormattedString() in the while overflow loop.
This snippet allow to draw points of a BezierPath ignoring quadratic added nodes when exporting a font.
def drawOnCurvePoints(bezierPath, size):
for c in bezierPath:
for p in c.points:
i = c.points.index(p)
try:
nextPoint = c.points[i+1]
except:
nextPoint = c.points[0]
previousPoint = c.points[i-1]
if nextPoint in bezierPath.onCurvePoints and previousPoint in bezierPath.onCurvePoints :
oval(p[0]-size/2,p[1]-size/2, size ,size)
if nextPoint[0] == p[0] and p in bezierPath.onCurvePoints:
oval(p[0]-size/2,p[1]-size/2, size ,size)
if previousPoint[0] == p[0] and p in bezierPath.onCurvePoints:
oval(p[0]-size/2,p[1]-size/2, size ,size)
if nextPoint[1] == p[1] and p in bezierPath.onCurvePoints:
oval(p[0]-size/2,p[1]-size/2, size ,size)
if previousPoint[1] == p[1] and p in bezierPath.onCurvePoints:
oval(p[0]-size/2,p[1]-size/2, size ,size)
Hi,
I tried to use
listNamedInstances(fontPath)
It seem to list the first instance (depending if variable font contain italic).
I test it with several Google Font and some of mine mine and the problem persists.
I check with FontTableViewer and all instances are present in [name] and [fvar] table.
I'm looking to not print :
*** DrawBot warning: [...] ***
Hi,
There is a way to not show DrawBot warning ?
@frederik Thanks for this clarification !
Hi,
I would like to translate a BezierPath, without changing it's bounds.
Here is code where you can see my problem.
newPage(2000,2000)
# Grey Rectangle
path0 = BezierPath()
path0.rect(1000,10,200,1990)
with savedState():
fill(0, 0.1)
drawPath(path0)
# Green Rectangle
path1 = BezierPath()
path1.text("1", fontSize=200)
with savedState():
fill(0,1,0)
rect(*path1.bounds())
drawPath(path1)
# Red Rectangle
path2 = BezierPath()
path2.text("2", fontSize=200, offset=(200,300))
with savedState():
fill(1,0,0)
rect(*path2.bounds())
drawPath(path2)
# Yellow Rectangle
path3 = BezierPath()
path3.text("3", fontSize=200)
path3.translate(100,800)
with savedState():
fill(1,1,0)
rect(*path3.bounds())
drawPath(path3)
# Magenta Rectangle
translate(900,800)
path4 = BezierPath()
path4.text("4", fontSize=200)
with savedState():
fill(1,0,1)
rect(*path4.bounds())
drawPath(path4)
I tested 3 solution:
use offset in path.text
Change BezierPath bounds
use path.translate
Change BezierPath bounds
use translate
Don't change BezierPath bounds
But this is annoying, because I don't want to translate all my canvas just for that.
So what is the solution ?
I just updated the repo with separated snippets for SublimeText.
Hi,
I recently uploaded snippets to add DrawBot auto-completion in VSCode, Atom and SublimeText.
You can access them from my GitHub Repo:
https://github.com/HugoJourdan/Drawbot-TextEditor-Snippets
It is possible to manually update Python version in drawBot ?
I'm facing a situation where I can't use a module inside drawBot because it uses Python 3.10
Snippet do draw rectangle with rounded corner:
def rectRounded(x,y,w,h,radius):
path = BezierPath()
sR=0.5*radius
w=w-radius
h=h-radius
path.rect(x,y+sR,w+radius,h)
path.rect(x+sR,y,w,h+radius)
path.oval(x,y,radius,radius)
path.oval(x+w,y,radius,radius)
path.oval(x,y+h,radius,radius)
path.oval(x+w,y+h,radius,radius)
path.removeOverlap()
drawPath(path)
It is possible to manually add it in drawBot module ?
I didn't know that option, thanks a lot frederik !
Hi,
I would like to ask users to select a folder and get his path. Here with my code, a window opens to choose the file but nothing happen after. Like if the script stop after the 3rd line.
from tkinter import Tk
from tkinter.filedialog import askdirectory
path = askdirectory(title='Select Folder') # shows dialog box and return the path
print(path)
No error message appears.
I put the complete tkinter module in the folder which contain the script.
There is a way to draw all glyphs from a .ttf in a textBox? Including all OpenType glyphs (like .ss01, .tf, .sc ...)
With listFontGlyphNames(), if I put the list in a textBox I get all names, but not drawings.
Hi,
I'm working on a script for Glyphs to build a Character set with Drawbot Extension. I'm using the Glyph API to extract the BezierPath of my letters.
I would like to set the x,y position of the Path without using translate
Here is my code :
from GlyphsApp import *
f = Glyphs.font # frontmost font
m = f.selectedFontMaster # active master
paperSize = 'A4Landscape'
newPage(paperSize)
scale (0.2, 0.2)
path = f.glyphs["A"].layers[m.id].completeBezierPath
drawPath(path)