I just updated the repo with separated snippets for SublimeText.

Snippet do draw rectangle with rounded corner:

def rectRounded(x,y,w,h,radius):
    path = BezierPath()
    sR=0.5*radius
    w=w-radius
    h=h-radius
    path.rect(x,y+sR,w+radius,h)
    path.rect(x+sR,y,w,h+radius)
    path.oval(x,y,radius,radius)
    path.oval(x+w,y,radius,radius)
    path.oval(x,y+h,radius,radius)
    path.oval(x+w,y+h,radius,radius)
    path.removeOverlap()
    drawPath(path)

It is possible to manually add it in drawBot module ?

I hadn't thought about this solution!
Thanks, @frederik!

newPage("A4Landscape")

box_w, box_h = width()-100, height()-100
box_x, box_y = 50, 50

txt = FormattedString()

txt.fontSize(90)
txt.align("center")
txt.append("LOOOOOOOOOOOOOOONG STRING\n"*30)

txt_w = textSize(txt)[0]
txt_h = textSize(txt)[1]

width_ratio = box_w/txt_w 
height_ratio = box_h/txt_h

sf = min(width_ratio , height_ratio, 1)

scale(sf)
textBox(txt, (box_x/sf, box_y/sf, box_w/sf, box_h/sf))

Hi,

I'm looking for a solution to find the maximum value of FontSize that can be set to allow a FormattedString() to occupy all the available space in a TextBox.

For TextBox using a simple string, I have already coded this snippet that returns the maximum fontSize value:

def get_max_fontSize_textBox(font, text, box, align=None, fS=200):
	font(FONT)
	fontSize(fS)
	hyphenation(False)
	overflow = textOverflow(text, box, align)
	while overflow:
		font(FONT)
		fS -= 1
		fontSize(fS)
		overflow = textOverflow(text, box, align)
return fS

I would like to achieve exactly the same thing, but using FormattedString() instead of a str.

The problem is how to build again the FormattedString() in the while overflow loop.

This snippet allow to draw points of a BezierPath ignoring quadratic added nodes when exporting a font.

def drawOnCurvePoints(bezierPath, size):
    for c in bezierPath:
        for p in c.points:
            i = c.points.index(p)
            try:
                nextPoint = c.points[i+1]
            except:
                nextPoint = c.points[0]
            previousPoint = c.points[i-1]

            if nextPoint in bezierPath.onCurvePoints and previousPoint in bezierPath.onCurvePoints :
                oval(p[0]-size/2,p[1]-size/2, size ,size)
        
            if nextPoint[0] == p[0] and p in bezierPath.onCurvePoints:
                oval(p[0]-size/2,p[1]-size/2, size ,size)
            
            if previousPoint[0] == p[0] and p in bezierPath.onCurvePoints:
                oval(p[0]-size/2,p[1]-size/2, size ,size)
            
            if nextPoint[1] == p[1] and p in bezierPath.onCurvePoints:
                oval(p[0]-size/2,p[1]-size/2, size ,size)
            
            if previousPoint[1] == p[1] and p in bezierPath.onCurvePoints:
                oval(p[0]-size/2,p[1]-size/2, size ,size)

Hi,

I tried to use

listNamedInstances(fontPath)

It seem to list the first instance (depending if variable font contain italic).

I test it with several Google Font and some of mine mine and the problem persists.

I check with FontTableViewer and all instances are present in [name] and [fvar] table.

I'm looking to not print :

*** DrawBot warning: [...] ***

Hi,

There is a way to not show DrawBot warning ?

@frederik Thanks for this clarification !

Hi,
I would like to translate a BezierPath, without changing it's bounds.

Here is code where you can see my problem.

newPage(2000,2000)

# Grey Rectangle
path0 = BezierPath()
path0.rect(1000,10,200,1990)
with savedState():
    fill(0, 0.1)
    drawPath(path0)

# Green Rectangle
path1 = BezierPath()
path1.text("1", fontSize=200)
with savedState():
    fill(0,1,0)
    rect(*path1.bounds())
drawPath(path1)

# Red Rectangle
path2 = BezierPath()
path2.text("2", fontSize=200, offset=(200,300))
with savedState():
    fill(1,0,0)
    rect(*path2.bounds())
drawPath(path2)

# Yellow Rectangle
path3 = BezierPath()
path3.text("3", fontSize=200)
path3.translate(100,800)
with savedState():
    fill(1,1,0)
    rect(*path3.bounds())
drawPath(path3)

# Magenta Rectangle
translate(900,800)
path4 = BezierPath()
path4.text("4", fontSize=200)
with savedState():
    fill(1,0,1)
    rect(*path4.bounds())
drawPath(path4)

I tested 3 solution:

• use offset in path.text
  Change BezierPath bounds

• use path.translate
  Change BezierPath bounds

• use translate
  Don't change BezierPath bounds

But this is annoying, because I don't want to translate all my canvas just for that.

So what is the solution ?

I just updated the repo with separated snippets for SublimeText.