Boolean and Rounded Corners

Lara

I have a code that generates a pattern of single rectangles according to a text input.

def letter_a():

    fill(0,0,0)
    rect (2*x,2*y, rectWidth, rectHeight)
    rect (3*x,2*y, rectWidth, rectHeight)
    rect (4*x,1*y, rectWidth, rectHeight)

    return letterWidth
        
def letter_b():
    fill(0,0,0)
    rect (2*x,2*y, rectWidth, rectHeight)
    rect (3*x,2*y, rectWidth, rectHeight)
    rect (3*x,1*y, rectWidth, rectHeight)

    return letterWidth  
    
#etc.

def drawLetter(func):
    with savedState():
        rotate(letterTilt, center=(letterWidth/2, 200))
        width = func()
    translate(width, 0)

textInput = "abcd\nefgh"


save()
for char in textInput:
    if char == "\n":
        restore()
        translate(0, -y*2)
        save()
    else:
        func = characterMap.get(char, draw_notdef)
        drawLetter(func)
 
saveImage("~/Desktop/Cyborg-Alphabet.svg")

This is the pattern it produces:
https://ibb.co/N94VFnH (sorry, the option to import an image doesn't seem to work)

I would like to 'stylise' the resulting pattern, with the equivalent of a Pathfinder in Illustrator and a rounded corner effect so it looks like that:
https://ibb.co/xhTwP19

Is there a way to do this in Drawbot?

frederik

he Lara!

Nice to see you continuing your drawBots!!

x, y = 300, 300
s = 100
# draw your rects as ovals
oval(x, y, s, s)
oval(x + s, y, s, s)
oval(x + s, y + s, s, s)
# build up connections with rects
rect(x + s/2, y, s, s)
rect(x + s, y + s/2, s, s)